How to match regular expression characters in right position, wrong order?
Question:
Say my string is bucs.
I would want to match buccaneers, tampa bay buccaneers, and bucs, but not "falcons".
I’m fairly new to regex, I tried:
re.findall("bucs", "buccaneers")
and it returned an empty list.
How would I go about doing this?
Answers:
You can separate your characters by .* to match strings in which they appear with no or some other characters between them:
In [1]: strs = "buccaneers", "tampa bay buccaneers", "bucs", "falcons"
In [2]: [s for s in strs if re.findall("b.*u.*c.*s", s)]
Out[2]: ['buccaneers', 'tampa bay buccaneers', 'bucs']
Say my string is bucs.
I would want to match buccaneers, tampa bay buccaneers, and bucs, but not "falcons".
I’m fairly new to regex, I tried:
re.findall("bucs", "buccaneers")
and it returned an empty list.
How would I go about doing this?
You can separate your characters by .* to match strings in which they appear with no or some other characters between them:
In [1]: strs = "buccaneers", "tampa bay buccaneers", "bucs", "falcons"
In [2]: [s for s in strs if re.findall("b.*u.*c.*s", s)]
Out[2]: ['buccaneers', 'tampa bay buccaneers', 'bucs']