Seaborn axvspan alterating x-axis

Question

I’m trying to create some scatter plots, with seaborn with a specific area of each plot highlighted in red. However when I add the code for axvspan, it changes the x-axis. This is how the plots look prior to axvspan being applied.

When i apply the line for axvpsan:

fig, (ax0, ax1) = plt.subplots(2,1, figsize=(5,10))

ax0.axvspan("0.4", "0.8", color='red', alpha=0.3, label ='Problem Area')
sns.scatterplot(x='Values_1', y='Values_2', data=df3, color='green', ax=ax0)
sns.scatterplot(x='Values_3', y='Values_4', data=df3, color='green', ax=ax1)
plt.show()

It sends up looking like this:

Ultimately, the red section needs to only cover the data between 0.4 and 0.7, but by altering the x-axis it ends up covering all of it.

Any advice?

Asked By: Mark

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Source

Answer 1

The unexpected behavior is resulting from passing the xmin and xmax arguments to matplotlib.pyplot.axvspan as str and not as float.

import matplotlib.pyplot as plt
import seaborn as sns
import numpy as np
import pandas as pd 

# generate data
rng = np.random.default_rng(12)
df3 = pd.DataFrame({"Values_2": rng.random(100), "Values_1": np.linspace(0., 0.6, 100)})

fig, ax0 = plt.subplots(1,1, figsize=(6, 4))
ax0.axvspan(0.4, 0.8, color='red', alpha=0.3, label ='Problem Area')

sns.scatterplot(x='Values_1', y='Values_2', data=df3, color='green', ax=ax0)
plt.show()

This gives:

Answered By: medium-dimensional

Seaborn axvspan alterating x-axis

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