Split string from digits/number according to sentence length
Question:
I have cases that I need to seperate chars/words from digits/numbers which are written consecutively, but I need to do this only when char/word length more than 3.
For example,
input
ferrari03
output must be:
ferrari 03
However, it shouldn’t do any action for the followings:
fe03, 03fe, 03ferrari etc.
Can you help me on this one ? I’m trying to do this without coding any logic, but re lib in python.
Answers:
Using re.sub() we can try:
inp = ["ferrari03", "fe03", "03ferrari", "03fe"]
output = [re.sub(r'^([A-Za-z]{3,})([0-9]+)$', r'1 2', i) for i in inp]
print(output) # ['ferrari 03', 'fe03', '03ferrari', '03fe']
Given an input word, the above regex will match should that word begin with 3 or more letters and end in 1 or more digits. In that case, we capture the letters and numbers in the 1 and 2 capture groups, respectively. We replace by inserting a separating space.
I have cases that I need to seperate chars/words from digits/numbers which are written consecutively, but I need to do this only when char/word length more than 3.
For example,
input
ferrari03
output must be:
ferrari 03
However, it shouldn’t do any action for the followings:
fe03, 03fe, 03ferrari etc.
Can you help me on this one ? I’m trying to do this without coding any logic, but re lib in python.
Using re.sub() we can try:
inp = ["ferrari03", "fe03", "03ferrari", "03fe"]
output = [re.sub(r'^([A-Za-z]{3,})([0-9]+)$', r'1 2', i) for i in inp]
print(output) # ['ferrari 03', 'fe03', '03ferrari', '03fe']
Given an input word, the above regex will match should that word begin with 3 or more letters and end in 1 or more digits. In that case, we capture the letters and numbers in the 1 and 2 capture groups, respectively. We replace by inserting a separating space.