How to do FizzBuzz challange with python?

Question

We have x number that goes 0 to 100. if x number divisible by 3 write ‘fizz’, if divisible by 5 write ‘buzz’ and if divisible by 3 and 5 write ‘fizzbuzz’.

What is wrong with this code below?

Code for FizzBuzz:

i = 1

while i <= 100:
 i = i + 1
 
 if (i % 3 == 0):
     print('Fizz')
 elif  (i % 5 == 0):
     print('Buzz')
 elif (i % 3 == 0) and (i % 5 == 0):
     print('FizzBuzz')
 else: print(i)

Asked By: rookie

||

Source

Answer 1

Your last elif will never be reached, because if it is divisible by 3 it will not continue, same with 5. So you need to take your last elif as first.

i = 1

while i <= 100:
 i = i + 1
 
 if (i % 3 == 0) and (i % 5 == 0):
     print('FizzBuzz')
 elif  (i % 5 == 0):
     print('Buzz')
 elif (i % 3 == 0):
     print('Fizz')
 else: print(i)

Answered By: Silas

Answer 2

Welcome! This might help you out:

i = 1

while i <= 100:
 answer = ''
 
 if (i % 15 == 0): print('FizzBuzz')
 elif (i % 3 == 0): print('Fizz')
 elif (i % 5 == 0): print('Buzz')
 else: print(i)
 
 i = i + 1

Basically, after you assigned a to 1, you instantly add another 1 in your while loop, so I moved your i = i + 1 to the bottom of the while loop.
Also, your 'FizzBuzz' wouldn’t be printed out – you skip if it divides both on 3 and 5, it divides by 15, but you skip that making fizzes and buzzes show in the first place and skipping the FizzBuzz. I fixed that too.

I hope it helped!

Answered By: stysan

How to do FizzBuzz challange with python?

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