How to match between the nth occurrence and nth +1 occurrence using regex

Question

I have the following text:

aBcD-19/WES/VA-MKL-2217223/2020

I would like to extract what is between the 2nd occurrence of / and the 3rd occurrence of /. Based on the text, the following will be extracted

VA-MKL-2217223

So far I came out with this pattern ‘S+?/’ which gives me 3 matches. That it, whats behind each /. I only want to depend on the slashes.

Asked By: Sarah cartenz

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Source

Answer 1

Given:

>>> s='aBcD-19/WES/VA-MKL-2217223/2020'

You can do:

>>> s.split('/')[2]
'VA-MKL-2217223'

Or with a regex:

>>> re.search(r'(?:[^/]+/){2}([^/]+)',s).group(1)
'VA-MKL-2217223'

Answered By: dawg

Answer 2

Here is a method that returns a string part between 2nd and third "/" (if there are more than two "/" characters in the string. Otherwise returns the string itself.

def find_string():
    my_str = "aBcD-19/WES/a"
    slices = my_str.split('/')
    if (len (slices)) > 2:
        return slices[2]
    return my_str

Answered By: Subhash Prajapati

How to match between the nth occurrence and nth +1 occurrence using regex

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