Slincing a pandas MultiIndex dataframe by one index where two row index value exist

Question

I wonder if anyone could please offer some advice:

I have a data set with the following structure:

import pandas as pd

# Creates pandas DataFrame.
df1 = pd.DataFrame({'Col1': [1, 2, 3, 4], 'Col2': [99, 98, 95, 90]}, index=['A', 'B', 'C', 'D'])
df2 = pd.DataFrame({'Col1': [1, 2], 'Col2': [99, 98]}, index=['A', 'B'])
df3 = pd.DataFrame({'Col1': [3, 4], 'Col2': [95, 90]}, index=['C', 'D'])

df_dict = dict(obj1=df1, obj2=df2, obj3=df3)

mDF = pd.concat(list(df_dict.values()), keys=list(df_dict.keys()))
mDF.rename_axis(index=["ID", "property"], inplace=True)
print(mDF)

These multi-index dataframes have different number of "property" rows:

               Col1  Col2
ID   property            
obj1 A            1    99
     B            2    98
     C            3    95
     D            4    90
obj2 A            1    99
     B            2    98
obj3 C            3    95
     D            4    90

For example, I would like to calculate the sum of Col1 values for property A and B or all IDs. However, this is only possible for obj ID which have both properties tabulated.

How could I slice this dataframe to those IDs which have the A and B proper

Asked By: Delosari

||

Source

Answer 1

Query works with named index:

mDF.query('property in ["A","B"]')

Output:

               Col1  Col2
ID   property            
obj1 A            1    99
     B            2    98
obj2 A            1    99
     B            2    98

Formatting the query string can be tricky sometimes. If you don’t feel comfortable with it, you can use Ben.T’s suggestion with .index.get_level_values.

Answered By: Quang Hoang

Slincing a pandas MultiIndex dataframe by one index where two row index value exist

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