if statement to identify directory path

Question

I’ve got watchdog and pyaudio playing together so if either of two directories is modified I hear a sound.

Now I’m trying to get a different sound for each directory. Watchdog can print the path that triggered it, so I’m trying to use that difference to fire each sound.

def on_modified(self, event,):
        x = event.src_path
        print(x)
        if x == 'c:/WATCHDOGTESTx.csv':
            pyaudio_01.PLAY_SOUND()
        if x == 'c:/WATCHDOGTEST2x.csv':
            pyaudio_02.PLAY_SOUND()

The print(x) works fine:

c:/WATCHDOGTEST2x.csv

however – the if statement won’t work – I get:

SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 16-17: truncated xXX escape

Any ideas appreciated!

Asked By: Dan S

||

Source

Answer 1

OK just figured it out – I added a forward slash to the target directory to get rid of the backslash it added itself, now it works. Doh.

Answered By: Dan S

Answer 2

Using x in the string, python interprets anything after x as hexadecimal charector, so you need to escape this charector, using one more slash.
So your value will be c:/WATCHDOGTEST\x.csv

Or you can turn it into raw string using r formater, r'c:/WATCHDOGTESTx.csv', this is the best way, beacuse it automatically ignores any special charectory if present.

Answered By: Lokesh Kurre

Answer 3

using built-in library pathlib would be more easy.

PureWindowsPath('c:/Program Files/').match(event.src_path)

Pure path objects provide path-handling operations which don’t actually access a filesystem. There are three ways to access these classes, which we also call flavours.

Answered By: KennetsuRinn

if statement to identify directory path

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