Convert complex comma-separated string into Python dictionary
Question:
I am getting following string format from csv file in Pandas
"title = matrix, genre = action, year = 2000, rate = 8"
How can I change the string value into a python dictionary like this:
movie = "title = matrix, genre = action, year = 2000, rate = 8"
movie = {
"title": "matrix",
"genre": "action",
"year": "1964",
"rate":"8"
}
Answers:
You can split the string and then convert it into a dictionary.
A sample code is given below
movie = "title = matrix, genre = action, year = 2000, rate = 8"
movie = movie.split(",")
# print(movie)
tempMovie = [i.split("=") for i in movie]
movie = {}
for i in tempMovie:
movie[i[0].strip()] = i[1].strip()
print(movie)
For the solution you can use regex
import re
input_user = "title = matrix, genre = action, year = 2000, rate = 8"
# Create a pattern to match the key-value pairs
pattern = re.compile(r"(w+) = ([w,]+)" )
# Find all matches in the input string
matches = pattern.findall(input_user)
# Convert the matches to a dictionary
result = {key: value for key, value in matches}
print(result)
The result:
{'title': 'matrix,', 'genre': 'action,', 'year': '2000,', 'rate': '8'}
I hope this can solve your problem.
movie = "title = matrix, genre = action, year = 2000, rate = 8"
dict_all_movies = {}
for idx in df.index:
str_movie = df.at[idx, str_movie_column]
movie_dict = dict(item.split(" = ") for item in str_movie.split(", "))
dict_all_movies[str(idx)] = movie_dict
I am getting following string format from csv file in Pandas
"title = matrix, genre = action, year = 2000, rate = 8"
How can I change the string value into a python dictionary like this:
movie = "title = matrix, genre = action, year = 2000, rate = 8"
movie = {
"title": "matrix",
"genre": "action",
"year": "1964",
"rate":"8"
}
You can split the string and then convert it into a dictionary.
A sample code is given below
movie = "title = matrix, genre = action, year = 2000, rate = 8"
movie = movie.split(",")
# print(movie)
tempMovie = [i.split("=") for i in movie]
movie = {}
for i in tempMovie:
movie[i[0].strip()] = i[1].strip()
print(movie)
For the solution you can use regex
import re
input_user = "title = matrix, genre = action, year = 2000, rate = 8"
# Create a pattern to match the key-value pairs
pattern = re.compile(r"(w+) = ([w,]+)" )
# Find all matches in the input string
matches = pattern.findall(input_user)
# Convert the matches to a dictionary
result = {key: value for key, value in matches}
print(result)
The result:
{'title': 'matrix,', 'genre': 'action,', 'year': '2000,', 'rate': '8'}
I hope this can solve your problem.
movie = "title = matrix, genre = action, year = 2000, rate = 8"
dict_all_movies = {}
for idx in df.index:
str_movie = df.at[idx, str_movie_column]
movie_dict = dict(item.split(" = ") for item in str_movie.split(", "))
dict_all_movies[str(idx)] = movie_dict