How to split string in every 6th strings which are the subsets of a dataframe column?

Question

In a dataframe column, I would like to split subset data in format of strings into every 6 digits and add a comma ‘,’ so that I can get a list of hs codes under the column. I tried the below but it needs some correction.

df.loc[df[:, 1] for i in range(0, len(['id'], 6)

Asked By: Seohyun Jeong

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Source

Answer 1

Assuming you want to split from the left:

df['id'] = df['id'].astype(str).str.replace(r'(.{6})(?=.)', r'1,', regex=True)

Output:

                     id
0  280530,284442,284690

Answered By: mozway

Answer 2

Code:

import pandas as pd

data = {'Column 1': ['a', 'b', 'c'],
        'id': [2468938493843983, 345642232, 23343433]}

df = pd.DataFrame(data)

df['id'] = df['id'].astype(str)
df['fromleft'] = [','.join([df['id'][i][j:j+6] for j in range(0, len(df['id'][i]), 6)]) for i in range(len(df))]

print(df)

Output:

  Column 1                id            fromleft
0        a  2468938493843983  246893,849384,3983
1        b         345642232          345642,232
2        c          23343433           233434,33

Answered By: Yash Mehta

How to split string in every 6th strings which are the subsets of a dataframe column?

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