How to make python multiple conditions into a single statement

Question

How to make the method below be returned in a single line?

Prefer to the #Note ## remarks below.

def falsify(leftover):
    #Note   ## Your code here (replace with a single line) ###
     
def falsify(leftover):
    false = []
    for num in leftover:
        if 30 > num > 20:
            false.append(num - 10)
        elif num >= 30:
            false.append('1' + (str(num[1:])))
        else:
            false.append(num)
     return false

I don’t have any other idea except breaking into 2 methods.

leftover1 = [19.7, 20.0, 28.5, 30.0, 30.7]

def process(leftover):
    false = []
    for num in leftover:
        print('num:' , num)

        if 30 > num >= 20: false.append(num - 10) 
        elif num >= 30:            
            # (str(num[1]))
            result = str(num)
            #print('result:' , result)
            false.append('1' + result[1:])
            #
        else:
            false.append(num)
    return false 


def falsify(leftover):
    #Note  ## Your code here (replace with a single line) ###
    return process(leftover)

print('result', falsify(leftover1))

Sample output as below

num: 19.7
num: 20.0
num: 28.5
num: 30.0
num: 30.7
result [19.7, 10.0, 18.5, '10.0', '10.7']

Asked By: Banana Tech

||

Source

Answer 1

You can do it with list comprehension:

def falsify(leftover): 
    return [num - 10 if 30 > num > 20 else ('1' + str(num[1:])) if num >= 30 else num for num in leftover]

Answered By: Jason Barnwell

Answer 2

leftover = [19.7, 20.0, 28.5, 30.0, 30.7]
def falsify(leftover):
    return [num - 10 if 30 > num >= 20 else ('1' + str(num)[1:]) if num >= 30 else num for num in leftover]

print('result', falsify(leftover))

# output
#result [19.7, 10.0, 18.5, '10.0', '10.7']

Answered By: God Is One

How to make python multiple conditions into a single statement

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