How to create rows of non-duplicating strings from a list?

Question

I want to create a 16X4 data frame with these coordinates as strings: "(.1,.1)","(-.1,-.1)","(-.1,.1)","(.1,-.1)". But, I do want not there to be duplicates.

To put it another way, the script would output a 16X4 matrix/dataframe like this:

"(.1,.1)","(-.1,-.1)","(-.1,.1)","(.1,-.1)"
"(-.1,.1)","(-.1,-.1)","(.1,.1)","(.1,-.1)"
"(-.1,-.1)","(.1,.1)","(-.1,.1)","(.1,-.1)" ...

In this way, I would get all the possible combinations of these four coordinates with no column duplicates.

I have been trying to brainstorm solutions. I know I can put them in an array and use random.choice() to randomly sample. But, I am not sure how to form this code in such a way where there will be no column duplicates and that patterns wont repeat.

Asked By: Kane York

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Source

Answer 1

Those are not strings. They are tuples of floating point values. You’re confusing things by using the wrong terminology.

import itertools
src = [(.1,.1),(-.1,-.1),(-.1,.1),(.1,-.1)]

for opt in itertools.permutations(src):
    print(opt)

If you really need the permutations in random order, then take the result into a list and shuffle:

import random
import itertools

src = [(.1,.1),(-.1,-.1),(-.1,.1),(.1,-.1)]
def makethem():
    vals = list(itertools.permutations(src))
    random.shuffle(vals)
    return vals[:16]

Answered By: Tim Roberts

How to create rows of non-duplicating strings from a list?

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