How to sum all the elements (except for the first one) in rows in 2d list?

Question

So, my task is to write a program which gets an integer on the input, then times asks for the student’s name (one word) and a space-separated list of their grades, and on the output there should be a list of tuples, where each tuple consists of the student’s name and their grade point average, rounded to integers.

Example:

Input:

3

Ann 5 6 7 8

Ben 10 10 0 0

Fred 7 6 8 5

Output:

[(‘Ann’, 6), (‘Ben’, 5), (‘Fred’, 6)]

Now my program looks like this:

n = int(input())
a = list()
for i in range(n):
  a.append(input().split())
print(tuple(a))

I have no idea how to sum numbers in each row (except for the first string, student’s name) and make it like a new list. Maybe I should somehow use numpy in this case, but still don’t know how. I will be grateful for any help

Asked By: Catherine

||

Source

Answer 1

Iterate over a and for each sublist, create a tuple out of the first item and the mean of the remaining items. You can use the built-in statistics.mean and then convert its result to an int:

from statistics import mean

n = int(input())
a = [input().split() for _ in range(n)]
result = [
    (name, int(mean(float(s) for s in scores)))
    for name, *scores in a
]
print(result)

Answered By: Samwise

Answer 2

After splitting each line on a space, the first element of the result is the name, and the rest of the elements are the grades.
Use sum to get the total of all grades, then divide by the number of grades to get the average.

n = int(input())
a = []
for i in range(n):
  name, *grades = input().split()
  a.append((name, round(sum(map(int, grades)) / len(grades))))
print(a)

Answered By: Unmitigated

How to sum all the elements (except for the first one) in rows in 2d list?

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