Is there a simpler way in python
Question:
I did the following to get from P13 to {P}{13}
import re
txt = "P13"
x = re.search("[A-T]", txt )
y = re.split("[A-T]", txt )
txt = "{" + x.group() + "}" + "{" + y[1] + "}"
It is working and gives what I want. But I’m wondering if there’s an easier way.
Answers:
You can try regex replace
out = re.sub('([A-T]+)(d+)', r'{1}{2}', txt)
$ print(out)
{P}{13}
Explanation:
-
1st Capturing Group ([A-T]+)
Match a single character present in the list [A-T] one and unlimited times
-
2nd Capturing Group (d+)
d matches a digit (equivalent to [0-9]) and + matches the previous token between one and unlimited times
I did the following to get from P13 to {P}{13}
import re
txt = "P13"
x = re.search("[A-T]", txt )
y = re.split("[A-T]", txt )
txt = "{" + x.group() + "}" + "{" + y[1] + "}"
It is working and gives what I want. But I’m wondering if there’s an easier way.
You can try regex replace
out = re.sub('([A-T]+)(d+)', r'{1}{2}', txt)
$ print(out)
{P}{13}
Explanation:
-
1st Capturing Group
([A-T]+)Match a single character present in the list
[A-T]one and unlimited times -
2nd Capturing Group
(d+)dmatches a digit (equivalent to[0-9]) and+matches the previous token between one and unlimited times