Regular Expression to remove a specific word which is not followed by a space

Question

WFH

STOPPED AT 2023 02 21 13 08 31

DURATION 01 50 56

NUMBER OF PARTICIPANTS 1

PARTICIPANTS

I have this problem statement where I want to remove the PARTICIPANTS which is on new line but doing so it removes the other PARTICIPANTS i.e.’NUMBER OF PARTICIPANTS 1′ this one. I don’t want that.

I have tried many regex but failed to find the desired the output. Either both of them get removed or none.

Help is really appreciated.

Thankyou in advance

Asked By: Mr. Dwivedi

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Source

Answer 1

Using a regex negative lookahead, you can specify that there is no space ahead.

import re

#The (n)? lets it match and remove the n newline marker behind the detected word if it is present, remove that if you want to keep the newline.
regex = r"(n)?PARTICIPANTS(?!s)"
string = "WFHnSTOPPED AT 2023 02 21 13 08 31nDURATION 01 50 56nNUMBER OF PARTICPANTS 1nPARTICIPANTS"

new_string = re.sub(regex, "", string)

#result of new_string
'WFHnSTOPPED AT 2023 02 21 13 08 31nDURATION 01 50 56nNUMBER OF PARTICPANTS 1'

Answered By: Shorn

Answer 2

You can use the multiline flag so that the ^ and $ anchors match at the start and end of each line. This way, you can replace the string "PARTICIPANTS" only when it’s on its own line.

re.sub(r"(?m)^PARTICIPANTS$", "", your_str)

Answered By: Unmitigated

Regular Expression to remove a specific word which is not followed by a space

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