how to remove space characters (" ")in a list {PYTHON}

Question

Im trying to write a for loop to remove space characters (" ") in my list but it’s just deleting some of the characters that are in the first of my lsit

this is my list

mylist=[" "," "," "," ","oho","abcd","1234",1234," "," ","omg"]

and this is my loop

for i in mylist:
    if i==' ':
        mylist.remove(i)

but when I print mylist I get this

[' ', 'oho', 'abcd', '1234', 1234, ' ', ' ', 'omg']

and I’m expecting this

['oho', 'abcd', '1234', 1234, 'omg']

Asked By: Not0_0Parsa

||

Source

Answer 1

here is with list compehension:

mylist=[" "," "," "," ","oho","abcd","1234",1234," "," ","omg"]
new_list=[x for x in mylist if x != " "]
print(new_list) # prints ['oho', 'abcd', '1234', 1234, 'omg']

Answered By: ilias-sp

Answer 2

One way is to use str.isspace() method:

[x for x in mylist if not str(x).isspace()]
#['oho', 'abcd', '1234', 1234, 'omg']

Reference: https://python-reference.readthedocs.io/en/latest/docs/str/isspace.html

Answered By: God Is One

Answer 3

Is this an XY problem ?

Just in case, if the reason you have such a list to begin with is that you were attempting to split a string while discarding all whitespace, but used str.split(), you may want to try re.split instead:

>>> import re
>>> data = '        oho abcd 1234     omg'
>>> re.split("s+", data.strip())
['oho', 'abcd', '1234', 'omg']

Answered By: Neutrinoceros

how to remove space characters (" ")in a list {PYTHON}

Question:

Answers: