Subtracting non-zero elements of a list in Python
Question:
I have a list n12. I want to subtract only non-zero elements of n12 from 1. I present the current and expected output.
n12=[0,
0.097055623870192,
0,
0.09668483656158318,
0.09983696710324882,
0.09905078620023211,
0.09857192019636203]
n22=[1-i for i in n12]
print(n22)
The current output is
[1, 0.902944376129808, 1, 0.9033151634384168, 0.9001630328967511, 0.9009492137997679, 0.9014280798036379]
The expected output is
[0, 0.902944376129808, 0, 0.9033151634384168, 0.9001630328967511, 0.9009492137997679, 0.9014280798036379]
Answers:
You can use conditions inside your loops.
n22=[1-i if i != 0 else i for i in n12]
Check the link for more details.
Python Conditions
You can use an if-else statement in your list comprehension:
>>> n12 = [0, 0.097055623870192, 0, 0.09668483656158318, 0.09983696710324882, 0.09905078620023211, 0.09857192019636203]
>>> n22 = [1 - x if x != 0 else 0 for x in n12]
>>> n22
[0, 0.902944376129808, 0, 0.9033151634384168, 0.9001630328967511, 0.9009492137997679, 0.9014280798036379]
You can have conditions in a list comprehension as follows:
n22 = [0 if e == 0 else 1-e for e in n12]
I have a list n12. I want to subtract only non-zero elements of n12 from 1. I present the current and expected output.
n12=[0,
0.097055623870192,
0,
0.09668483656158318,
0.09983696710324882,
0.09905078620023211,
0.09857192019636203]
n22=[1-i for i in n12]
print(n22)
The current output is
[1, 0.902944376129808, 1, 0.9033151634384168, 0.9001630328967511, 0.9009492137997679, 0.9014280798036379]
The expected output is
[0, 0.902944376129808, 0, 0.9033151634384168, 0.9001630328967511, 0.9009492137997679, 0.9014280798036379]
You can use conditions inside your loops.
n22=[1-i if i != 0 else i for i in n12]
Check the link for more details.
Python Conditions
You can use an if-else statement in your list comprehension:
>>> n12 = [0, 0.097055623870192, 0, 0.09668483656158318, 0.09983696710324882, 0.09905078620023211, 0.09857192019636203]
>>> n22 = [1 - x if x != 0 else 0 for x in n12]
>>> n22
[0, 0.902944376129808, 0, 0.9033151634384168, 0.9001630328967511, 0.9009492137997679, 0.9014280798036379]
You can have conditions in a list comprehension as follows:
n22 = [0 if e == 0 else 1-e for e in n12]