I am unable to understand the function of code

Question

def something(number):
  return number%3==0
def nothing(number):
  return number%5==0
def anything(number):
  total=0
  for i in range(number):
     if something or nothing:
         total+=i
  output=(total//5)//33
  return output

#the output should be predicted for anything(1000)

I couldn’t understand the flow of function here.

Asked By: Ananya Tiwari

||

Source

Answer 1

As John mentioned, without the parenthesis and arguments ‘something’ and ‘nothing’ are considered truthy values in the if statement. You’re not calling the functions. Something like this should work:

def anything(number):
  total = 0
  for i in range(number)
    if something(i) or nothing(i):
      total += i
  output = (total // 5) // 33
  return output

Answered By: sstab

Answer 2

I’m analyzing this program, which is the code in the question, except for the if line, which is changed according to the comment by Johh Gordon and the answer by sstab:

def something(number):
  return number%3==0
def nothing(number):
  return number%5==0
def anything(number):
  total=0
  for i in range(number):
     if something(i) or nothing(i):
         total+=i
  output=(total//5)//33
  return output
print(anything(1000))

In total, it computes the sum of integers in 0 .. 999 (both inclusive) which are divisible by 3 or divisible by 5.

Sum of integers divisible by 3: 0 + 3 + … + 999 = (0 + 999) * 334 / 2 = 166833.
Sum of integers divisible by 5: 0 + 5 + … + 995 = (0 + 995) * 200 / 2 = 99500.
Sum of integers divisible by 15: 0 + 15 + … + 990 = (0 + 990) * 67 / 2 = 33165.
total = 166833 + 99500 – 33165 = 233168.
output = (233168 // 5) // 33 = 1413.

And, indeed, it prints 1413 when run.

Answered By: pts

Answer 3

In this answer I’m analyzing the code in the original question. As noted by John Gordon and sstab, it is unusual, because the functions are not called, so the if ...: is always true. Thus the code is equivalent to:

def anything(number):
  total=0
  for i in range(number):
     if True:
         total+=i
  output=(total//5)//33
  return output
print(anything(1000))

In total, it computes the sum of integers in 0 .. 999 (both inclusive):

Sum of integers: 0 + … + 999 = (0 + 999) * 1000 / 2 = 499500.
output = (499500 // 5) // 33 = 3027.

And, indeed, it prints 3027 when run.

Answered By: pts

Answer 4

I assume that part of the correct code is like this:

if something(i) or nothing(i):

instead of

if something or nothing:

The code can be explained below:

def something(number):
  return number%3==0

def nothing(number):
  return number%5==0

def anything(number):
  total=0
  for i in range(number):
     if something(i) or nothing(i):
         total+=i
  output = (total//5)//33
  return output

anything(1000)
# run anything(1000) with number == 1000
# total == 0
# do loop 0 to 999
# - loop with i == 0:
# -- run something(0) -> return 0 mod 3 == 0 -> return 0 == 0 -> return true
# -- run nothing(0) -> return 0 mod 5 == 0 -> return 0 == 0 -> return true
# -- if true or true --> if true
# --- total = 0 + 1 -> 1
# - loop with i == 1:
# -- run something(1) -> return 1 mod 3 == 0 -> return 1 == 0 -> return false
# -- run nothing(1) -> return 1 mod 5 == 0 -> return 1 == 0 -> return false
# -- if false or false --> if false -> dont run "total+=i"
# .
# .
# .
# - loop with i == 999:
# -- run something(999) -> return 999 mod 3 == 0 -> return 1 == 0 -> return false
# -- run nothing(999) -> return 999 mod 5 == 0 -> return 4 == 0 -> return false
# -- if false or false --> if false -> dont run "total+=i"
# total == 233168
# output = (total//5)//33 -> (233168//5)//33 -> 46633//33 -> 1413
# finally, anything(1000) return 1413

So the result of anything(1000) function should be 1413

Answered By: Jordy

I am unable to understand the function of code

Question:

Answers: