how can I merge grpc client and http request?
Question:
I want to merge http request and grpc client that means:
I have a request for create some object.
my service is gateway that means it sends data in celery task and grpc client sends a request and receive stream responses.
when should i run this client? should i run the client in same function that sends data in celery task or not?
I am really confused.
Answers:
It’s not recommended to run the gRPC client and the Celery task in the same function as it can lead to blocking the event loop and reduce the scalability of your application. Instead, you can run the gRPC client in a separate function and call that function from the Celery task.
import grpc
import my_pb2
import my_pb2_grpc
from celery import Celery
app = Celery('myapp', broker='redis://localhost:6379/0')
def grpc_client():
# Create gRPC channel and stub
channel = grpc.insecure_channel('localhost:50051')
stub = my_pb2_grpc.MyServiceStub(channel)
# Create gRPC request
request = my_pb2.MyRequest(data='hello')
# Call gRPC method and process stream responses
responses = stub.MyMethod(request)
for response in responses:
# Process each response
print(response)
@app.task
def create_object(data):
# Send data to Celery task
# ...
# Call gRPC client function
grpc_client()
# Return response from Celery task
# ...
In this example, the grpc_client() function creates a gRPC channel and stub, creates a gRPC request, calls a gRPC method, and processes stream responses. The create_object() function sends data to the Celery task and then calls the grpc_client() function to process the data using gRPC.
Note that the gRPC client function is defined outside of the Celery task function and is called asynchronously, which allows the Celery task to continue running and processing other requests while the gRPC client processes the data in the background.
I want to merge http request and grpc client that means:
I have a request for create some object.
my service is gateway that means it sends data in celery task and grpc client sends a request and receive stream responses.
when should i run this client? should i run the client in same function that sends data in celery task or not?
I am really confused.
It’s not recommended to run the gRPC client and the Celery task in the same function as it can lead to blocking the event loop and reduce the scalability of your application. Instead, you can run the gRPC client in a separate function and call that function from the Celery task.
import grpc
import my_pb2
import my_pb2_grpc
from celery import Celery
app = Celery('myapp', broker='redis://localhost:6379/0')
def grpc_client():
# Create gRPC channel and stub
channel = grpc.insecure_channel('localhost:50051')
stub = my_pb2_grpc.MyServiceStub(channel)
# Create gRPC request
request = my_pb2.MyRequest(data='hello')
# Call gRPC method and process stream responses
responses = stub.MyMethod(request)
for response in responses:
# Process each response
print(response)
@app.task
def create_object(data):
# Send data to Celery task
# ...
# Call gRPC client function
grpc_client()
# Return response from Celery task
# ...
In this example, the grpc_client() function creates a gRPC channel and stub, creates a gRPC request, calls a gRPC method, and processes stream responses. The create_object() function sends data to the Celery task and then calls the grpc_client() function to process the data using gRPC.
Note that the gRPC client function is defined outside of the Celery task function and is called asynchronously, which allows the Celery task to continue running and processing other requests while the gRPC client processes the data in the background.