Remove double quotes only if it between character Python
Question:
I have a string inside variable a contains double quotation inside double quotations :
Input :
a = ""comment_text": "Siti Sa"diah I need this for my neighbor needs""
Expected result :
a = ""comment_text": "Siti Sadiah I need this for my neighbor needs""
I tried using
re.sub(r'[^A-Za-z]', '', a)
and I also tried this one:
re.sub('"', '', a)
but it resulting like this :
commenttextSitiSadiahIneedthisformyneighborneeds
and this
comment_text: Siti Sadiah I need this for my neighbor needs
I want to delete double quotation(") only if it between alphabets.
I’m using python for this one. Is anyone could find a way to solve this issue ?
Thanks a lot!
Answers:
re.sub(r'(w)"(w)', r'12', df['comment']) for any word character around "
Try this regex :
r'b"b'
The b is called a word boundary. It matches the position between a word character and a non-word character (in this case "), or the beginning or end of the string.
I have a string inside variable a contains double quotation inside double quotations :
Input :
a = ""comment_text": "Siti Sa"diah I need this for my neighbor needs""
Expected result :
a = ""comment_text": "Siti Sadiah I need this for my neighbor needs""
I tried using
re.sub(r'[^A-Za-z]', '', a)
and I also tried this one:
re.sub('"', '', a)
but it resulting like this :
commenttextSitiSadiahIneedthisformyneighborneeds
and this
comment_text: Siti Sadiah I need this for my neighbor needs
I want to delete double quotation(") only if it between alphabets.
I’m using python for this one. Is anyone could find a way to solve this issue ?
Thanks a lot!
re.sub(r'(w)"(w)', r'12', df['comment']) for any word character around "
Try this regex :
r'b"b'
The b is called a word boundary. It matches the position between a word character and a non-word character (in this case "), or the beginning or end of the string.