how to convert H(b < g) = 2*100 – H(b < g) from MATLAB to python

Question

I have the MATLAB code like below

H = [10 20 30 40 50 60]
b = [5 9 28 59 22 18]
g = [9 9 10 25 30 5]

H(b < g) = 2*100 - H(b < g)

the result is like this :

H = 
    190    20    30    40    150    60

I think this code means that if b[index] < g[index] then H[index] = 2*100 - H[index]

Is my understanding is correct?
Is there way in python to do it without looping for the index?

Asked By: KEZIA ANGELINE

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Source

Answer 1

To make it in just one line.
If b or g are too short, this code will raise an exception.

H = [2*100 - h if b[inx] < g[inx] else h
     for inx, h in enumerate(H)]

As have already been said in the comments, if you have a lot of code from Matlab to "translate" into Python, you better use numpy.

Answered By: Jorge Luis

Answer 2

Your understanding of the code is correct: the MATLAB code checks which elements of b are less than the corresponding element of g, and changes only those corresponding elements of H to 200 - H.

Since you’re already using numpy, translating MATLAB is quite straightforward: just change the parentheses to brackets.

H = np.array([10, 20, 30, 40, 50, 60])
b = np.array([5, 9, 28, 59, 22, 18])
g = np.array([9, 9, 10, 25, 30, 5])

H[b < g] = 2*100 - H[b < g]

Which gives the desired H:

array([190,  20,  30,  40, 150,  60])

Here’s a handy resource for translating MATLAB to numpy: https://numpy.org/doc/stable/user/numpy-for-matlab-users.html

Answered By: Pranav Hosangadi

how to convert H(b < g) = 2*100 – H(b < g) from MATLAB to python

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