List the content of a directory mssparkutils

Question

I used the following code to list the files in a directory but it is showing the entire path instead of just the file name:

historical_logs_adls_path = (
    f"abfss://{staging_container_name}@{staging_account_name}.dfs.core.windows.net/"
    f"{staging_dirname}"
 )


mssparkutils.fs.ls("/")
mssparkutils.fs.ls(historical_logs_adls_path)

I simply need the list of files.

Asked By: Lopa

||

Source

Answer 1

Use basename function: https://www.geeksforgeeks.org/python-os-path-basename-method/

Try the below:

import os

historical_logs_adls_path = (
    f"abfss://{staging_container_name}@{staging_account_name}.dfs.core.windows.net/"
    f"{staging_dirname}"
 )

file_list = [os.path.basename(file.path) for file in mssparkutils.fs.ls(historical_logs_adls_path)]
print(file_list)

Answered By: Abdulmajeed

List the content of a directory mssparkutils

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