How to split python dataframe rows in one to one mapping form?

Question

I’m trying to split python dataframe rows to one to one mapping format such that each new line represents the value in the same order as the column in front and if there is a single value on other columns copy their value in the new created row, like:

A	B	C
valueA1	valueB1 valueB2 valueB3	valueC1 valueC2 valueC3
valueA2	valueB4	valueC4

Should split like:

A	B	C
valueA1	valueB1	valueC1
valueA1	valueB2	valueC2
valueA1	valueB3	valueC3
valueA2	valueB4	valueC4

Here all values are string type.

I did tried explode() but that was not splitting in one to one format, any help is really appreciated!

Asked By: Sakshi Sharma

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Source

Answer 1

You need to turn your columns to lists by splitting the lines and then explode them

In [28]: df
Out[28]: 
         A                          B                          C
0  valueA1  ValueB1nValueB2nValueB3  ValueC1nValueC2nValueC3
1  valueA2                    ValueB4                    ValueC4

In [29]: df.apply(lambda col: col.str.split()).explode("A").explode(["B", "C"])
Out[29]: 
         A        B        C
0  valueA1  ValueB1  ValueC1
0  valueA1  ValueB2  ValueC2
0  valueA1  ValueB3  ValueC3
1  valueA2  ValueB4  ValueC4

Answered By: zaki98

Answer 2

This solution only focuses on columns B and C:

df1[['B', 'C']] = df1[['B', 'C']].apply(lambda x: x.str.split('n'))
df1 = df1.explode(list('BC'))
df1
         A        B        C
0  valueA1  valueB1  valueC1
0  valueA1  valueB2  valueC2
0  valueA1  valueB3  valueC3
1  valueA2  valueB4  valueC4

Answered By: Marcelo Paco

How to split python dataframe rows in one to one mapping form?

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