Filter on json data with in_() sqlalchemy

Question

I want to filter features(Json field on database) with items = a or b, but here it returns 0, when I use other columns the filter works correctly. It returns correct data with ["a"] or ["b"] too, what is the reason? and what is the solution?

data.filter(Data.id.in_([1,2])) #works

data.filter(Data.features['items'].in_(["a"])) # returns 3

data.filter(Data.features['items'].in_(["b"])) # returns 1

data.filter(Data.features['items'].in_(["a","b"])) # returns 0 I exepect 4

Asked By: parastoo

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Source

Answer 1

I am guessing here, but you might be looking to use contains instead of in_.

Please try the below queries instead:

q = select(Data).filter(Data.features['items'].contains("a"))
q = select(Data).filter(Data.features['items'].contains("b"))
q = select(Data).filter(or_(  # i assume it is OR, but you might have wanted AND instead
    Data.features['items'].contains("a"), 
    Data.features['items'].contains("b"),
))

Answered By: van

Answer 2

data.filter(Data.features[‘items’].in_(["a","b"])) returns 0 because data.filter() is looking features with BOTH ‘a’ and ‘b’ in the items field.

if you only want either ‘a’ or ‘b’ you’ll need to filter with an ‘or’ operator from sqlalchemy import.

data.filter(or_(Data.features['items'].in_(["a"]), Data.features['items'].in_(["b"])))

Answered By: Simran Farrukh

Filter on json data with in_() sqlalchemy

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