How to find keys in second dictionary which has different value compare to first dictionary

Question

I can use diff = set(dict2) - set(dict1) to know that the dict1 and dict2 are not equal but what I need is to find which KEY in dict2 has a different value than dict1

 dict1 = {'c1': 'Iran', 'c2': 'India', 'c3': 'Iraq', 'c4': 'Qatar'}
 dict2 = {'c1': 'Iran', 'c2': 'India', 'c3': 'Iraqs','c4': 'Qeter'}
 diff = set(dict2) - set(dict1)
 print(diff)

Basically what I want to get in return are {'c3', 'c4'}

Asked By: Behseini

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Source

Answer 1

Use for loop to check same key in different dict.

dict1 = {'c1': 'Iran', 'c2': 'India', 'c3': 'Iraq', 'c4': 'Qatar'}
dict2 = {'c1': 'Iran', 'c2': 'India', 'c3': 'Iraqs', 'c4': 'Qeter'}
diff = {k for k in dict2 if dict2[k] != dict1[k]}
print(diff)

Output:

{'c4', 'c3'}

Answered By: Shuo

Answer 2

You can do like this,

keys = set()
for key in dict1:
    if key in dict2 and dict1[key] != dict2[key]:
        keys.add(key)

print(keys)

output:

{'c3', 'c4'}

Answered By: Ajeet Verma

Answer 3

You can do like below:

dict1 = {'c1': 'Iran', 'c2': 'India', 'c3': 'Iraq', 'c4': 'Qatar'}
dict2 = {'c1': 'Iran', 'c2': 'India', 'c3': 'Iraqs', 'c4': 'Qeter'}
diff = set(dict2.items())-set(dict1.items())
diff_dict = dict(diff)
print(diff_dict.keys())

Answered By: Hetvi

How to find keys in second dictionary which has different value compare to first dictionary

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