How to use subprocess.run with correct path on windows?
Question:
On windows 10 using python 3.10.10 I am trying to run a windows executable, but there is some issue with the path to the folder of the executable. I am trying to run the following code
path = r"C:/Program Files (x86)/STMicroelectronics/STM32Cube/STM32CubeProgrammer/bin"
result = subprocess.run(command, cwd=path)
but I get the error
FileNotFoundError: [WinError 2] The system cannot find the file specified
(with and without the r).
I guess I have to "convert" the path somehow? But how exactly?
Also, the path DOES exist, and I am using similar path expressions (with the slash (/)) for other windows paths in the same python application running on windows.
Answers:
According to the warning in the documentation here, windows cannot overwrite the current working directory unless you supply shell=True. Therefore, your method call would look like this:
result = subprocess.run(command, cwd=path, shell=True)
On windows 10 using python 3.10.10 I am trying to run a windows executable, but there is some issue with the path to the folder of the executable. I am trying to run the following code
path = r"C:/Program Files (x86)/STMicroelectronics/STM32Cube/STM32CubeProgrammer/bin"
result = subprocess.run(command, cwd=path)
but I get the error
FileNotFoundError: [WinError 2] The system cannot find the file specified
(with and without the r).
I guess I have to "convert" the path somehow? But how exactly?
Also, the path DOES exist, and I am using similar path expressions (with the slash (/)) for other windows paths in the same python application running on windows.
According to the warning in the documentation here, windows cannot overwrite the current working directory unless you supply shell=True. Therefore, your method call would look like this:
result = subprocess.run(command, cwd=path, shell=True)