How do i write a string letter by letter using concatenation in python

Question

I currently have a way to write a string letter by letter but when i try and include more arguments it gives me the error that it was expecting 1 and not 3

I used this to define

def delay_print(s):
    for c in s:
        sys.stdout.write(c)
        sys.stdout.flush()
        time.sleep(0.25)

i then tried this code:

delay_print("You have" ,lives, "lives left")

and then go the error:

    delay_print("You have" ,lives, "lives left")
TypeError: delay_print() takes 1 positional argument but 3 were given

Asked By: oscar

||

Source

Answer 1

Thats because you pass 3 arguments. The comma separates the arguments a function recieves. what you can do is

delay_print("You have" + lives + "lives left")

or more fancy with the f-string syntax.

delay_print(f"You have {lives} lives left")

Answered By: Melon Pie

Answer 2

You could use a variable number of arguments like this:

import sys
import time

def delay_print(*args):
    for s in args:
        for c in str(s):
            sys.stdout.write(c)
            sys.stdout.flush()
            time.sleep(0.25)

delay_print("You have ", 2, " lives left")

Output:

You have 2 lives left

Answered By: DarkKnight

How do i write a string letter by letter using concatenation in python

Question:

Answers: