What is the difference between exhausting a generator using "for i in generator" and next(generator)
Question:
I want to learn how to use the return value of a generator (but this not what I’m concerned with now).
After searching, they said that I can get the return value from StopIteration
when the generator is exhausted, so I tested it with the following code:
def my_generator():
yield 1
yield 2
yield 3
return "done"
def exhaust_generator(_gen):
print("===============================================n")
print("exhaust_generator")
try:
while True:
print(next(_gen))
except StopIteration as e:
print(f"Return value: '{e.value}'")
def exhaust_generator_iter(_gen):
print("===============================================n")
print("exhaust_generator_iter")
try:
for i in _gen:
print(i)
print(next(_gen))
except StopIteration as e:
print(f"Return value: {e.value}")
gen = my_generator()
gen2 = my_generator()
exhaust_generator(gen)
exhaust_generator_iter(gen2)
===============================================
exhaust_generator
1
2
3
Return value: 'done'
===============================================
exhaust_generator_iter
1
2
3
Return value: None
As you can see, the return value is different between the two versions of exhausting the generator and I wonder why.
Searched google but it has not been helpful.
Answers:
In your first example with the while
, you’re catching the first StopIteration
exception raised by the generator when it’s initially exhausted.
In your second example with the for
, you’re catching a subsequent StopIteration
exception raised by calling next()
a second time after the generator has already been exhausted (by the for
, which caught that initial exception).
As far as I understand, the for
loop internally also calls next()
and eventually catches the StopIteration
, so it knows when to stop calling next()
.
Your next()
call in exhaust_generator_iter
then raises a second StopIteration
but without the passed value.
This SO question and its answers explore ways to receive the return
value from a generator, i.a. using a utility class or dependency injection.
I want to learn how to use the return value of a generator (but this not what I’m concerned with now).
After searching, they said that I can get the return value from StopIteration
when the generator is exhausted, so I tested it with the following code:
def my_generator():
yield 1
yield 2
yield 3
return "done"
def exhaust_generator(_gen):
print("===============================================n")
print("exhaust_generator")
try:
while True:
print(next(_gen))
except StopIteration as e:
print(f"Return value: '{e.value}'")
def exhaust_generator_iter(_gen):
print("===============================================n")
print("exhaust_generator_iter")
try:
for i in _gen:
print(i)
print(next(_gen))
except StopIteration as e:
print(f"Return value: {e.value}")
gen = my_generator()
gen2 = my_generator()
exhaust_generator(gen)
exhaust_generator_iter(gen2)
===============================================
exhaust_generator
1
2
3
Return value: 'done'
===============================================
exhaust_generator_iter
1
2
3
Return value: None
As you can see, the return value is different between the two versions of exhausting the generator and I wonder why.
Searched google but it has not been helpful.
In your first example with the while
, you’re catching the first StopIteration
exception raised by the generator when it’s initially exhausted.
In your second example with the for
, you’re catching a subsequent StopIteration
exception raised by calling next()
a second time after the generator has already been exhausted (by the for
, which caught that initial exception).
As far as I understand, the for
loop internally also calls next()
and eventually catches the StopIteration
, so it knows when to stop calling next()
.
Your next()
call in exhaust_generator_iter
then raises a second StopIteration
but without the passed value.
This SO question and its answers explore ways to receive the return
value from a generator, i.a. using a utility class or dependency injection.