How to create a class instance directly with a call to a class method?
Question:
I’m facing a problem that I can’t solve. Is it possible to make pipe be an instance of the class MyClass concerning the call to the class method do_something? And make print(isinstance(pipe, MyClass)) return True. This means that on the call pipe goes through the class method do_something and then reads the constructor __init__
.
class MyClass:
def __init__(self):
self.my_attr = 42
print("Attribute initialized to", self.my_attr)
@classmethod
def do_something(cls):
print("Doing something...")
pipe = MyClass.do_something()
print(isinstance(pipe, MyClass)) # True
Answers:
To create an instance of MyClass and call the do_something
method on it you can modify the code like this
class MyClass:
def __init__(self):
self.my_attr = 42
print("Attribute initialized to", self.my_attr)
@classmethod
def do_something(cls):
obj = cls()
print("Doing something...")
return obj
pipe = MyClass.do_something()
print(isinstance(pipe, MyClass)) # True
You could do this with the walrus operator:
(pipe:=MyClass()).do_something()
print(isinstance(pipe, MyClass))
Yes, you can create a class instance directly with a call to a class method by returning an instance of the class within the class method. In this case, you can modify the do_something
method to create an instance of MyClass
and return it. The code for it is as follows:
class MyClass:
def __init__(self):
self.my_attr = 42
print("Attribute initialized to", self.my_attr)
@classmethod
def do_something(cls):
print("Doing something...")
return cls() # Create an instance of MyClass and return it
pipe = MyClass.do_something()
print(isinstance(pipe, MyClass)) # True
Now, when you call MyClass.do_something()
, it will create an instance of MyClass
and return it. As a result, pipe
becomes an instance of MyClass
, and isinstance(pipe, MyClass)
returns True
.
Output:
Doing something...
Attribute initialized to 42
True
I’m facing a problem that I can’t solve. Is it possible to make pipe be an instance of the class MyClass concerning the call to the class method do_something? And make print(isinstance(pipe, MyClass)) return True. This means that on the call pipe goes through the class method do_something and then reads the constructor __init__
.
class MyClass:
def __init__(self):
self.my_attr = 42
print("Attribute initialized to", self.my_attr)
@classmethod
def do_something(cls):
print("Doing something...")
pipe = MyClass.do_something()
print(isinstance(pipe, MyClass)) # True
To create an instance of MyClass and call the do_something
method on it you can modify the code like this
class MyClass:
def __init__(self):
self.my_attr = 42
print("Attribute initialized to", self.my_attr)
@classmethod
def do_something(cls):
obj = cls()
print("Doing something...")
return obj
pipe = MyClass.do_something()
print(isinstance(pipe, MyClass)) # True
You could do this with the walrus operator:
(pipe:=MyClass()).do_something()
print(isinstance(pipe, MyClass))
Yes, you can create a class instance directly with a call to a class method by returning an instance of the class within the class method. In this case, you can modify the do_something
method to create an instance of MyClass
and return it. The code for it is as follows:
class MyClass:
def __init__(self):
self.my_attr = 42
print("Attribute initialized to", self.my_attr)
@classmethod
def do_something(cls):
print("Doing something...")
return cls() # Create an instance of MyClass and return it
pipe = MyClass.do_something()
print(isinstance(pipe, MyClass)) # True
Now, when you call MyClass.do_something()
, it will create an instance of MyClass
and return it. As a result, pipe
becomes an instance of MyClass
, and isinstance(pipe, MyClass)
returns True
.
Output:
Doing something...
Attribute initialized to 42
True