Search string that contains WORD with W or ^ before and W or $ after
Question:
How to simplify following regular expression
re.search(f'W{word}W', text) or re.search(f'^{word}W', text) or re.search(f'W{word}$', text) or word == text
i.e. return True for any string that contains word with W or ^ before and W or $ after.
Variants
re.search(f'[^W]{word}[W$]', text)re.search(f'[W^]{word}[W$]', text)
dont work for my case.
Expression re.search(f'W*{word}W*', text) gives wrong matches, for example word + 'A'.
Any suggestions? Thank you!
Answers:
There is no simple way to make ^ or $ optional patterns in Python’s regexps.
I think the easiest way will be to concatenate the three regexps, but using the | operator inside the expression instead of the external or with 3 .search calls:
word = re.escape(ticker.lower())
result = re.search(f"(^{word}W)|(W{word}W)|(W{word}$)"`
How to simplify following regular expression
re.search(f'W{word}W', text) or re.search(f'^{word}W', text) or re.search(f'W{word}$', text) or word == text
i.e. return True for any string that contains word with W or ^ before and W or $ after.
Variants
re.search(f'[^W]{word}[W$]', text)re.search(f'[W^]{word}[W$]', text)
dont work for my case.
Expression re.search(f'W*{word}W*', text) gives wrong matches, for example word + 'A'.
Any suggestions? Thank you!
There is no simple way to make ^ or $ optional patterns in Python’s regexps.
I think the easiest way will be to concatenate the three regexps, but using the | operator inside the expression instead of the external or with 3 .search calls:
word = re.escape(ticker.lower())
result = re.search(f"(^{word}W)|(W{word}W)|(W{word}$)"`