Removing elements of one list wth respect to the other in Python
Question:
I have lists J and Indices. I want to remove elements of J according to locations specified in Indices. For example, Indices[0]=1 and Indices[1]=2. This means that J[0][1] and J[0][2] should be removed in one go. But I am getting an error. I present the expected output.
Indices=[1,2]
J=[[2, 3, 6, 7, 9, 10]]
J=J[0].remove(Indices[0])
print(J)
The error is
in <module>
J=J[0].remove(Indices[0])
ValueError: list.remove(x): x not in list
The expected output is
[[2, 7, 9, 10]]
Answers:
Use this
Indices = [1, 2]
J = [[2, 3, 6, 7, 9, 10]]
for index in sorted(Indices, reverse=True):
J[0].pop(index)
print(J)
remove: remove the element that is passed in it, error if the element is not in the list.
pop: remove the element on the index that is passed in it, if no index provide then it will remove the last element[-1 index], if the index is not correct then error.
I have lists J and Indices. I want to remove elements of J according to locations specified in Indices. For example, Indices[0]=1 and Indices[1]=2. This means that J[0][1] and J[0][2] should be removed in one go. But I am getting an error. I present the expected output.
Indices=[1,2]
J=[[2, 3, 6, 7, 9, 10]]
J=J[0].remove(Indices[0])
print(J)
The error is
in <module>
J=J[0].remove(Indices[0])
ValueError: list.remove(x): x not in list
The expected output is
[[2, 7, 9, 10]]
Use this
Indices = [1, 2]
J = [[2, 3, 6, 7, 9, 10]]
for index in sorted(Indices, reverse=True):
J[0].pop(index)
print(J)
remove: remove the element that is passed in it, error if the element is not in the list.
pop: remove the element on the index that is passed in it, if no index provide then it will remove the last element[-1 index], if the index is not correct then error.