how to split the string wtih brackets?

Question

I’d like to splitt the below string into something like this
'180-240','0-100','100-200','0-110','200-240','0-120'

a='(180-240,0-100),(100-200,0-110),(200-240,0-120)'
a
'(180-240,0-100),(100-200,0-110),(200-240,0-120)'

After the below split, it is still one element of string, I am expecting to get a lsit with 3 tuples of

['(180-240,0-100','100-200,0-110','200-240,0-120)']

However I got below a list with only one string. Not sure where is the problem? Thanks


b=a.split('(,)')
b
['(180-240,0-100),(100-200,0-110),(200-240,0-120)']

Asked By: roudan

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Answer 1

One of many possible solutions, use re:

import re

a = "(180-240,0-100),(100-200,0-110),(200-240,0-120)"

print(re.findall(r"[^)(,]+", a))

Prints:

['180-240', '0-100', '100-200', '0-110', '200-240', '0-120']

Answer 2

A common pattern here would be to use the built-in str.split method:

source = '(180-240,0-100),(100-200,0-110)'
split_up = source.split(',')
cleaned = [v.strip('()') for v in split_up]

Answered By: Jules

Question: