TypeError: 'builtin_function_or_method' object is not subscriptable

Question:

elif( listb[0] == "-test"):
    run_all.set("testview")
    listb.pop[0]

ERROR: Exception in Tkinter callback Traceback (most recent call
last): File
“/tools/python/2.7.2/lib/python2.7/lib-tk/Tkinter.py”, line 1410,
in call
return self.func(*args) File “./edit.py”, line 581, in populate
listb.pop[0] TypeError: ‘builtin_function_or_method’ object is not subscriptable

The line # 581 is represented by last pop statement in the code above.
run_all is a StringVar.

Why am I getting this error and how can it be solved?

Asked By: Ani

||

Answers:

I think you want

listb.pop()[0]

The expression listb.pop is a valid python expression which results in a reference to the pop method, but doesn’t actually call that method. You need to add the open and close parentheses to call the method.

Answered By: srgerg

You are trying to access pop as if was a list or a tupple, but pop is not. It’s a method.

Answered By: c0m4

instead of writing listb.pop[0] write

listb.pop()[0]
         ^
         |
Answered By: a ghost

This error arises when you don’t use brackets with pop operation. Write the code in this manner.

listb.pop(0)

This is a valid python expression.

Answered By: Tushar Palawat

Looks like you typed brackets instead of parenthesis by mistake.

Answered By: Aamir M Meman

FYI, this is not an answer to the post. But it may help future users who may get the error with the message:

TypeError: ‘builtin_function_or_method’ object is not subscriptable

In my case, it was occurred due to bad indentation.

Just indenting the line of code solved the issue.

Answered By: Bhojendra Rauniyar

Mad a similar error, easy to fix:

    TypeError Traceback (most recent call last) <ipython-input-2-1eb12bfdc7db> in <module>
  3 mylist = [10,20,30] ----> 4 arr = np.array[(10,20,30)] 5 d = {'a':10, 'b':20, 'c':30} TypeError: 'builtin_function_or_method' object is not subscriptable

but I should have written it as:

arr = np.array([10,20,30])

Very fixable, rookie/dumb mistake.

Answered By: Quantum Prophet

Can’t believe this thread was going on for so long.
You would get this error if you got distracted
and used [] instead of (), at least my case.

Pop is a method on the list data type,
https://docs.python.org/2/tutorial/datastructures.html#more-on-lists

Therefore, you shouldn’t be using pop as if it was a list itself, pop[0].
It’s a method that takes an optional parameter representing an index,
so as Tushar Palawat pointed out in one of the answers that didn’t get approved,
the correct adjustment which will fix the example above is:

listb.pop(0)

If you don’t believe, run a sample such as:

if __name__ == '__main__':
  listb = ["-test"]
  if( listb[0] == "-test"):
    print(listb.pop(0))

Other adjustments would work as well, but it feels as they are abusing the Python language. This thread needs to get fixed, not to confuse users.

Addition,
a.pop() removes and returns the last item in the list.
As a result, a.pop()[0] will get the first character of that
last element. It doesn’t seem that is what the given code snippet
is aiming to achieve.

Answered By: Konstantin Grigorov
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