How can I check if a URL is absolute using Python?

Question

What is the preferred solution for checking if an URL is relative or absolute?

Asked By: Geo

||

Answer 1

If you want to know if an URL is absolute or relative in order to join it with a base URL, I usually do urllib.parse.urljoin anyway:

>>> from urllib.parse import urljoin
>>> urljoin('http://example.com/', 'http://example.com/picture.png')
'http://example.com/picture.png'
>>> urljoin('http://example1.com/', '/picture.png')
'http://example1.com/picture.png'
>>>

Answered By: warvariuc

Answer 2

Python 2

You can use the urlparse module to parse an URL and then you can check if it’s relative or absolute by checking whether it has the host name set.

>>> import urlparse
>>> def is_absolute(url):
...     return bool(urlparse.urlparse(url).netloc)
... 
>>> is_absolute('http://www.example.com/some/path')
True
>>> is_absolute('//www.example.com/some/path')
True
>>> is_absolute('/some/path')
False

Python 3

urlparse has been moved to urllib.parse, so use the following:

from urllib.parse import urlparse

def is_absolute(url):
    return bool(urlparse(url).netloc)

Answered By: Lukáš Lalinský

Answer 3

Can’t comment accepted answer, so write this comment as new answer: IMO checking scheme in accepted answer ( bool(urlparse.urlparse(url).scheme) ) is not really good idea because of http://example.com/file.jpg, https://example.com/file.jpg and //example.com/file.jpg are absolute urls but in last case we get scheme = ”

I use this code:

is_absolute = True if '//' in my_url else False

Answered By: Alexander Ovchinnikov

Answer 4

pip install yarl

import yarl

if not yarl.URL(image).is_absolute():
    image = context["request"].build_absolute_uri(image)

because

yarl.URL("//google.com").is_absolute() is True
True

in the opposite to

urllib.parse.urlsplit("//google.com").scheme == ""
True

netloc is still defined though

urllib.parse.urlsplit("//google.com").netloc == "google.com"

Answered By: Belegnar

How can I check if a URL is absolute using Python?

Question:

Answers:

Python 2

Python 3