How to get day name from datetime


How can I get the day name (such as Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday) from a datetime object in Python?

So, for example, datetime(2019, 9, 6, 11, 33, 0) should give me "Friday".

Asked By: gadss



import datetime
now =

See the Python docs for, datetime.strftime and more on strftime.

Answered By: Matt Joiner
>>> from datetime import datetime as date
Answered By: Abhijit
import datetime
numdays = 7
base =
date_list = [base + datetime.timedelta(days=x) for x in range(numdays)]
date_list_with_dayname = ["%s, %s" % ((base + datetime.timedelta(days=x)).strftime("%A"),  base + datetime.timedelta(days=x)) for x in range(numdays)]
Answered By: user3769499

If you don’t mind using another package, you can also use pandas to achieve what you want:

>>> my_date = datetime.datetime(2019, 9, 6, 11, 33, 0)
>>> pd.to_datetime(my_date).day_name()

It does not sound like a good idea to use another package for such easy task, the advantage of it is that day_name method seems more understandable to me than strftime("%A") (you might easily forget what is the right directive for the format to get the day name).

Hopefully, this could be added to datetime package directly one day (e.g. my_date.day_name()).

Answered By: Nerxis

You can use import time instead of datetime as following:

import time
WEEKDAYS = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']

now = time.localtime()
weekday_index = now.tm_wday
Answered By: Appo

You can use an f-string along with a format code such as %A or %a:

> import datetime

# Provide a date object:
> d =
> d, 2, 3)

# Provide a datetime object:
> dt =
> dt
datetime.datetime(2023, 2, 3, 17, 48, 7, 415010)

# Full weekday name:
> f'{d:%A}'
> f'{dt:%A}'

# Abbreviated weekday name:
> f'{d:%a}'
> f'{dt:%a}'

Note that the output strings are locale dependent. If requiring a locale independent comparison or even just a faster comparison, consider date.weekday() and datetime.weekday().

Answered By: Asclepius
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