Is there a quiet version of subprocess.call?

Question

Is there a variant of subprocess.call that can run the command without printing to standard out, or a way to block out it’s standard out messages?

Asked By: fergusdawson

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Source

Answer 1

Yes. Redirect its stdout to /dev/null.

process = subprocess.call(["my", "command"], stdout=open(os.devnull, 'wb'))

Answered By: Matt Joiner

Answer 2

Often that kind of chatter is coming on stderr, so you may want to silence that too. Since Python 3.3, subprocess.call has this feature directly:

To suppress stdout or stderr, supply a value of DEVNULL.

Usage:

import subprocess
rc = subprocess.call(args, stderr=subprocess.DEVNULL, stdout=subprocess.DEVNULL)

If you are still on Python 2:

import os, subprocess

with open(os.devnull, 'wb') as shutup:
    rc = subprocess.call(args, stdout=shutup, stderr=shutup)

Answered By: wim

Answer 3

This is a recipe I use a lot: call subprocess and collect the output, and when the command succeeds discard the output, but when it fails print the output.

import subprocess as sp
import sys

if "print" in __builtins__.__dict__:
    prn = __builtins__.__dict__["print"]
else:
    def prn(*args, **kwargs):
        """
        prn(value, ..., sep=' ', end='\n', file=sys.stdout)
        Works just like the print function in Python 3.x but can be used in 2.x.

        Prints the values to a stream, or to sys.stdout by default.
        Optional keyword arguments:
        file: a file-like object (stream); defaults to the current sys.stdout.
        sep:  string inserted between values, default a space.
        end:  string appended after the last value, default a newline.
        """
        sep = kwargs.get("sep", ' ')
        end = kwargs.get("end", 'n')
        file = kwargs.get("file", sys.stdout)

        s = sep.join(str(x) for x in args) + end
        file.write(s)


def rc_run_cmd_basic(lst_cmd, verbose=False, silent=False):
    if silent and verbose:
        raise ValueError("cannot specify both verbose and silent as true")

    p = sp.Popen(lst_cmd, stdin=sp.PIPE, stdout=sp.PIPE, stderr=sp.PIPE)
    tup_output = p.communicate()

    s_cmd = ' '.join(lst_cmd)
    if verbose:
        prn()
        prn("command: '%s'n" % s_cmd)

        if 0 != p.returncode:
            prn()
            prn("Command failed with code %d:" % p.returncode)
        else:
            prn("Command succeeded!  code %d" % p.returncode)
    if verbose:
        prn("Output for: " + s_cmd)
        prn(tup_output[0])
        prn()
    if not silent and 0 != p.returncode:
        prn("Error output for: " + s_cmd)
        prn(tup_output[1])
        prn()

    return p.returncode

Answered By: steveha

Answer 4

I use subprocess.check_output in such cases and drop the return value. You might want to add a comment your code stating why you are using check_output in place of check_call. check_output is also nicer when a failure occurs and you are interested in the error output. Example code below. The output is seen only when you uncomment the print line. If the command fails, an exception is thrown.

import subprocess
ret = subprocess.check_output(["cat", "/tmp/1"])
#print ret

Answered By: Jay Rajput

Is there a quiet version of subprocess.call?

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