How do I get the current file, current class, and current method with Python?

Question

Name of the file from where code is running
Name of the class from where code is running
Name of the method (attribute of the class) where code is running

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Answer 1

self.__class__.__name__  # name of class i'm in

for the rest the sys and trace modules

http://docs.python.org/library/sys.html
http://docs.python.org/library/trace.html

Some more info:
https://mail.python.org/pipermail/python-list/2001-August/096499.html
and
http://www.dalkescientific.com/writings/diary/archive/2005/04/20/tracing_python_code.html

did you want it for error reporting because the traceback module can handle that:

http://docs.python.org/library/traceback.html

Answered By: SpliFF

Answer 2

Here is an example of each:

from inspect import stack

class Foo:
    def __init__(self):
        print __file__
        print self.__class__.__name__
        print stack()[0][3]

f = Foo()

Answered By: Andrew Hare

Answer 3

import sys

class A:
    def __init__(self):
        print __file__
        print self.__class__.__name__
        print sys._getframe().f_code.co_name

a = A()

Answered By: mtasic85

Answer 4

Be very careful. Consider:

class A:
    pass

B = A
b = B()

What is the ‘class name’ of b here? Is it A, or B? Why?

The point is, you shouldn’t need to know or care. An object is what it is: its name is very rarely useful.

Answered By: Daniel Roseman

How do I get the current file, current class, and current method with Python?

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