Extracting zip file contents to specific directory in Python 2.7

Question

This is the code I am currently using to extract a zip file that lives in the same current working directory as the script. How can I specify a different directory to extract to?

The code I tried is not extracting it where I want.

import zipfile

fh = open('test.zip', 'rb')
z = zipfile.ZipFile(fh)
for name in z.namelist():
    outfile = open(name, 'wb')
    outfile.write('C:\'+z.read(name))
    outfile.close()
fh.close()

Asked By: lodkkx

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Source

Answer 1

Peter de Rivaz has a point in the comment above. You are going to want to have the directory in the call to open().
You are going to want to do something like this:

import zipfile
import os

os.mkdir('outdir')
fh = open('test.zip','rb')
z = zipfile.ZipFile(fh)
for name in z.namelist():
    outfile = open('outdir'+'/'+name, 'wb')
    outfile.write()
    outfile.close()
fh.close()

Answered By: ratmatz

Answer 2

I think you’ve just got a mixup here. Should probably be something like the following:

import zipfile

fh = open('test.zip', 'rb')
z = zipfile.ZipFile(fh)
for name in z.namelist():
    outpath = "C:\"
    z.extract(name, outpath)
fh.close()

and if you just want to extract all the files:

import zipfile

with zipfile.ZipFile('test.zip', "r") as z:
    z.extractall("C:\")

Use pip install zipfile36 for recent versions of Python

import zipfile36

Answered By: secretmike

Answer 3

I tried the other answers in this thread, but the final solution for me was simply:

zfile = zipfile.ZipFile('filename.zip')
zfile.extractall(optional_target_folder)

Look at extractall, but use it only with trustworthy zip files.

Answered By: fiatjaf

Answer 4

I’ve modified the code to ask the user input the file name and its path where it need to be extracted and so the user will’ve more control on where to put the extracted folder and what name should be assigned to the extracted folder.

import zipfile

#picking zip file from the directory
ZipFileName = raw_input("Enter full path to zip file:")  
fh = open( ZipFileName , 'rb')
z = zipfile.ZipFile(fh)

#assigning a name to the extracted zip folder
DestZipFolderName = raw_input("Assign destination folder a name: ")
DestPathName = raw_input("Enter destination directory: ")
DestPath = DestPathName + "\" + DestZipFolderName

for name in z.namelist():   
    outpath = DestPath
    z.extract(name, outpath)
fh.close()

Answered By: MD SARFARAZ

Answer 5

Adding to secretmike’s answer above with support for python 2.6 for extracting all files.

import zipfile
import contextlib


with contextlib.closing(zipfile.ZipFile('test.zip', "r")) as z:
   z.extractall("C:\")

Answered By: Slakker

Answer 6

If you just want to extract a zip file from the command line using Python (say because you don’t have the unzip command available), then you can call the zipfile module directly

python -m zipfile -e monty.zip target-dir/

Take a look at the docs. It also supports compression and listing the contents.

Answered By: Peter Gibson

Extracting zip file contents to specific directory in Python 2.7

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