super() raises "TypeError: must be type, not classobj" for new-style class

Question

The following use of super() raises a TypeError: why?

>>> from  HTMLParser import HTMLParser
>>> class TextParser(HTMLParser):
...     def __init__(self):
...         super(TextParser, self).__init__()
...         self.all_data = []
...         
>>> TextParser()
(...)
TypeError: must be type, not classobj

There is a similar question on StackOverflow: Python super() raises TypeError, where the error is explained by the fact that the user class is not a new-style class. However, the class above is a new-style class, as it inherits from object:

>>> isinstance(HTMLParser(), object)
True

What am I missing? How can I use super(), here?

Using HTMLParser.__init__(self) instead of super(TextParser, self).__init__() would work, but I would like to understand the TypeError.

PS: Joachim pointed out that being a new-style-class instance is not equivalent to being an object. I read the opposite many times, hence my confusion (example of new-style class instance test based on object instance test: https://stackoverflow.com/revisions/2655651/3).

Asked By: Eric O Lebigot

||

Source

Answer 1

If you look at the inheritance tree (in version 2.6), HTMLParser inherits from SGMLParser which inherits from ParserBase which doesn’t inherits from object. I.e. HTMLParser is an old-style class.

About your checking with isinstance, I did a quick test in ipython:

In [1]: class A:
   ...:     pass
   ...: 

In [2]: isinstance(A, object)
Out[2]: True

Even if a class is old-style class, it’s still an instance of object.

Answered By: Some programmer dude

Answer 2

super() can be used only in the new-style classes, which means the root class needs to inherit from the ‘object’ class.

For example, the top class need to be like this:

class SomeClass(object):
    def __init__(self):
        ....

not

class SomeClass():
    def __init__(self):
        ....

So, the solution is that call the parent’s init method directly, like this way:

class TextParser(HTMLParser):
    def __init__(self):
        HTMLParser.__init__(self)
        self.all_data = []

Answered By: Colin Su

Answer 3

Alright, it’s the usual “super() cannot be used with an old-style class”.

However, the important point is that the correct test for “is this a new-style instance (i.e. object)?” is

>>> class OldStyle: pass
>>> instance = OldStyle()
>>> issubclass(instance.__class__, object)
False

and not (as in the question):

>>> isinstance(instance, object)
True

For classes, the correct “is this a new-style class” test is:

>>> issubclass(OldStyle, object)  # OldStyle is not a new-style class
False
>>> issubclass(int, object)  # int is a new-style class
True

The crucial point is that with old-style classes, the class of an instance and its type are distinct. Here, OldStyle().__class__ is OldStyle, which does not inherit from object, while type(OldStyle()) is the instance type, which does inherit from object. Basically, an old-style class just creates objects of type instance (whereas a new-style class creates objects whose type is the class itself). This is probably why the instance OldStyle() is an object: its type() inherits from object (the fact that its class does not inherit from object does not count: old-style classes merely construct new objects of type instance). Partial reference: https://stackoverflow.com/a/9699961/42973.

PS: The difference between a new-style class and an old-style one can also be seen with:

>>> type(OldStyle)  # OldStyle creates objects but is not itself a type
classobj
>>> isinstance(OldStyle, type)
False
>>> type(int)  # A new-style class is a type
type

(old-style classes are not types, so they cannot be the type of their instances).

Answered By: Eric O Lebigot

Answer 4

You can also use class TextParser(HTMLParser, object):. This makes TextParser a new-style class, and super() can be used.

Answered By: Valentin Lorentz

Answer 5

the correct way to do will be as following in the old-style classes which doesn’t inherit from ‘object’

class A:
    def foo(self):
        return "Hi there"

class B(A):
    def foo(self, name):
        return A.foo(self) + name

Answered By: Jacob Abraham

Answer 6

The problem is that super needs an object as an ancestor:

>>> class oldstyle:
...     def __init__(self): self.os = True

>>> class myclass(oldstyle):
...     def __init__(self): super(myclass, self).__init__()

>>> myclass()
TypeError: must be type, not classobj

On closer examination one finds:

>>> type(myclass)
classobj

But:

>>> class newstyle(object): pass

>>> type(newstyle)
type

So the solution to your problem would be to inherit from object as well as from HTMLParser.
But make sure object comes last in the classes MRO:

>>> class myclass(oldstyle, object):
...     def __init__(self): super(myclass, self).__init__()

>>> myclass().os
True

Answered By: user2070206

Answer 7

FWIW and though I’m no Python guru I got by with this

>>> class TextParser(HTMLParser):
...    def handle_starttag(self, tag, attrs):
...        if tag == "b":
...            self.all_data.append("bold")
...        else:
...            self.all_data.append("other")
...     
...         
>>> p = TextParser()
>>> p.all_data = []
>>> p.feed(text)
>>> print p.all_data
(...)

Just got me the parse results back as needed.

Answered By: qwerty_so

super() raises "TypeError: must be type, not classobj" for new-style class

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