How to calculate a mod b in Python?
Question:
Is there a modulo function in the Python math library?
Isn’t 15 % 4, 3? But 15 mod 4 is 1, right?
Answers:
There’s the % sign. It’s not just for the remainder, it is the modulo operation.
Why don’t you use % ?
print 4 % 2 # 0
mod = a % b
This stores the result of a mod b in the variable mod.
And you are right, 15 mod 4 is 3, which is exactly what python returns:
>>> 15 % 4
3
a %= b is also valid.
>>> 15 % 4
3
>>>
The modulo gives the remainder after integer division.
you can also try divmod(x, y) which returns a tuple (x // y, x % y)
I don’t think you’re fully grasping modulo. a % b and a mod b are just two different ways to express modulo. In this case, python uses %. No, 15 mod 4 is not 1, 15 % 4 == 15 mod 4 == 3.
A = [3, 1, 2, 4]
for a in A:
print(a % 2)
output:
1
1
0
0
Is there a modulo function in the Python math library?
Isn’t 15 % 4, 3? But 15 mod 4 is 1, right?
There’s the % sign. It’s not just for the remainder, it is the modulo operation.
Why don’t you use % ?
print 4 % 2 # 0
mod = a % b
This stores the result of a mod b in the variable mod.
And you are right, 15 mod 4 is 3, which is exactly what python returns:
>>> 15 % 4
3
a %= b is also valid.
>>> 15 % 4
3
>>>
The modulo gives the remainder after integer division.
you can also try divmod(x, y) which returns a tuple (x // y, x % y)
I don’t think you’re fully grasping modulo. a % b and a mod b are just two different ways to express modulo. In this case, python uses %. No, 15 mod 4 is not 1, 15 % 4 == 15 mod 4 == 3.
A = [3, 1, 2, 4]
for a in A:
print(a % 2)
output:
1
1
0
0