match dates using python regular expressions

Question

I want to match dates that have the following format:

2010-08-27,
2010/08/27

Right now I am not very particular about the date being actually feasible, but just that it is in the correct format.

please tell the regular expression for this.

Thanks

Asked By: user1308308

||

Source

Answer 1

You can use the datetime module to parse dates:

import datetime

print datetime.datetime.strptime('2010-08-27', '%Y-%m-%d')
print datetime.datetime.strptime('2010-15-27', '%Y-%m-%d')

output:

2010-08-27 00:00:00
Traceback (most recent call last):
  File "./x.py", line 6, in <module>
    print datetime.datetime.strptime('2010-15-27', '%Y-%m-%d')
  File "/usr/lib/python2.7/_strptime.py", line 325, in _strptime
    (data_string, format))
ValueError: time data '2010-15-27' does not match format '%Y-%m-%d'

So catching ValueError will tell you if the date matches:

def valid_date(datestring):
    try:
        datetime.datetime.strptime(datestring, '%Y-%m-%d')
        return True
    except ValueError:
        return False

To allow for various formats you could either test for all possibilities, or use re to parse out the fields first:

import datetime
import re

def valid_date(datestring):
        try:
                mat=re.match('(d{2})[/.-](d{2})[/.-](d{4})$', datestring)
                if mat is not None:
                        datetime.datetime(*(map(int, mat.groups()[-1::-1])))
                        return True
        except ValueError:
                pass
        return False

Answered By: hochl

Answer 2

Use the datetime module. Here is a regex for the sake of knowledge although you shouldn’t use it:

r'd{4}[-/]d{2}[-/]d{2}'

Answered By: jamylak

Answer 3

You can use this code:

import re

# regular expression to match dates in format: 2010-08-27 and 2010/08/27 
# date_reg_exp = re.compile('(d+[-/]d+[-/]d+)')

updated regular expression below:

# regular expression to match dates in format: 2010-08-27 and 2010/08/27
# and with mixed separators 2010/08-27
# date_reg_exp = re.compile('d{4}[-/]d{2}[-/]d{2}')

# if separators should not be mixed use backreference:
date_reg_exp = re.compile('d{4}(?P<sep>[-/])d{2}(?P=sep)d{2}')

# a string to test the regular expression above
test_str= """
     fsf2010/08/27sdfsdfsd
     dsf sfds f2010/08/26 fsdf 
     asdsds 2009-02-02 afdf
     """
# finds all the matches of the regular expression and
# returns a list containing them
matches_list=date_reg_exp.findall(test_str)

# iterates the matching list and prints all the matches
for match in matches_list:
  print match

Answered By: Thanasis Petsas

Answer 4

dateutil package has a quite smart dates parser. It parses a wide range of dateformats.
http://pypi.python.org/pypi/python-dateutil

Answered By: Maksym Polshcha

Answer 5

use this:

test_str= '''
     fsf2010/08/27sdfsdfsd
     dsf sfds f2010/08/26 fsdf 
     asdsds 2009-02-02 afdf
     '''

date_regex = re.compile('d{4}[/.-]d{2}[/.-]d{2}')    
  
for match in date_regex.findall(test_str):
    print(match)

output:

2010/08/27
2010/08/26
2009-02-02

Answered By: jPro

match dates using python regular expressions

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