element

Get all table elements in Python using Selenium Question: I have a webpage which looks like this: <table class="data" width="100%" cellpadding="0" cellspacing="0"> <tbody> <tr> <th>1</th> <th>2</th> <th>3 by</th> </tr> <tr> <td width="10%"><a href="foo1">5120432</a></td> <td width="70%">INTERESTED_SITE1/</td> <td width="20%"><a href="foo2">foo2</a></td> </tr> <tr class="alt"> <td width="10%"><a href="foo1">5120431</a></td> <td width="70%">INTERESTED_SITE2</td> <td width="20%"><a href="foo2">foo2</a></td> </tr> </tbody> </table> I want to …

Remove odd-indexed elements from list in Python Question: I’m trying to remove the odd-indexed elements from my list (where zero is considered even) but removing them this way won’t work because it throws off the index values. lst = [‘712490959’, ‘2’, ‘623726061’, ‘2’, ‘552157404’, ‘2’, ‘1285252944’, ‘2’, ‘1130181076’, ‘2’, ‘552157404’, ‘3’, ‘545600725’, ‘0’] def remove_odd_elements(lst): …

How to count items in JSON data Question: How I can get the number of elements in node of JSON data? JSON: { “result”:[ { “run”:[ { “action”:”stop” }, { “action”:”start” }, { “action”:”start” } ], “find”:true } ] } I need to get the number of elements from node data[‘result’][0][‘run’]. It should be 3, …

Access multiple elements of list knowing their index Question: I need to choose some elements from the given list, knowing their index. Let say I would like to create a new list, which contains element with index 1, 2, 5, from given list [-2, 1, 5, 3, 8, 5, 6]. What I did is: a …

Numpy ValueError: setting an array element with a sequence. This message may appear without the existing of a sequence? Question: Why do I get this error message? ValueError: setting an array element with a sequence. Thank you Z=np.array([1.0,1.0,1.0,1.0]) def func(TempLake,Z): A=TempLake B=Z return A*B Nlayers=Z.size N=3 TempLake=np.zeros((N+1,Nlayers)) kOUT=np.zeros(N+1) for i in xrange(N): kOUT[i]=func(TempLake[i],Z) Asked By: …

Python Filtering 2 Lists Question: I’m trying to find a way to use one list to filter out elements of another. Kinda like the intersect syntax but the exact opposite lst = [0,1,2,6] secondlst = [0,1,2,3,4,5,6] expected outcome [3,4,5] Asked By: HighAllegiant || Source Answers: Simple way: r = [v for v in secondlst if …

Finding max value in the second column of a nested list? Question: I have a list like this: alkaline_earth_values = [[‘beryllium’, 4], [‘magnesium’, 12], [‘calcium’, 20], [‘strontium’, 38], [‘barium’, 56], [‘radium’, 88]] If I simply use the max(list) method, it will return the answer ‘strontium’, which would be correct if I was trying to find …