Python : List Comprehensn with IF/ELSE statement
Python : List Comprehensn with IF/ELSE statement Question: I’m looking for an oneliner for this below logic: links (list) variable will contain = [‘**www.google.com/api/1.js**’,’**/path.js**’] url = "mysite.com" valid_links = [url + u for u in links if not urlparse(u).netloc ] This will give me only [‘mysite.com/path.js’] but not ‘www.google.com‘ in the list. I need full …