Is it possible to modify a variable in python that is in an outer (enclosing), but not global, scope? Question: Consider this example: def A(): b = 1 def B(): # I can access ‘b’ from here. print(b) # But can i modify ‘b’ here? B() A() For the code in the B function, the …
Python nonlocal statement in a class definition Question: I’m trying to perform some analysis of scope in Python 3 source code and I’m stuck with how the nonlocal statement statement works inside a class definition. As I understand it, the class definition executes its body inside a new namespace (call it dict) and binds the …
How do I access outer functions variables inside a closure(python 2.6)? Question: From wikipedia I need to access outer functions variables in a similar manner as using the ‘nonlocal’ keyword from python 3.x. Is there some way to do that in python 2.6? (Not necessarily using the nonlocal keyword) Asked By: Thiago Padilha || Source …
What does "nonlocal" do in Python 3? Question: What does nonlocal do in Python 3.x? To close debugging questions where OP needs nonlocal and doesn’t realize it, please use Is it possible to modify variable in python that is in outer, but not global, scope? instead. Although Python 2 is officially unsupported as of January …
