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if statement not printing correctly when adding elif Question: I wrote the following code to create a url from users choice, def create_parameter_url(weather_data): list_parameters = str(input(‘Would you like to see available parameters? y/n n>>>’)) for i in range(len(weather_data[‘resource’])): if list_parameters == ‘y’: print(i+1 , ":" , weather_data[‘resource’][i][‘title’] , weather_data[‘resource’][i][‘summary’]) choose_parameter = str(input(‘nEnter the index of …

How to split on a delimiter in python preserving the delimiter Question: so what i wanna do here is basically i have a file with a list of url endpoints, and i wanna split the links in the file on the slash delimter, basically generating sub-endpoints of endpoints, example: https://www.somesite.com/path1/path2/path3 and i would want to …

Django : HttpRequest.__init__() takes 1 positional argument but 2 were given Question: So I simply want when I click on the particular article to output its slug, for example if the slug of the given article is django-rules then i want it to be outputted as django-rules when i click on it. just that here …

Why using validators=[URLValidator] when defining a model CharField doesn't make it check for URL-validity upon saving the corresponding ModelForm? Question: app.models.py: from django.core.validators import URLValidator from django.db import models class Snapshot(models.Model): url = models.CharField(max_length=1999, validators=[URLValidator]) app.forms.py: from django import forms from .models import Snapshot class SnapshotForm(forms.ModelForm): class Meta: model = Snapshot fields = (‘url’,) app.views.py: …

from blog.views import (blog_post_detail_page), SyntaxError: invalid syntax Question: hi I was trying to use run server for my Django app that i have created in my directory that looks like this I was getting this error during runserver from blog.views import (blog_post_detail_page), SyntaxError: invalid syntax ` 1-try_django *src *blog init.py admin.py app.py models.py test.py views.py …

Iterate over a txt file of urls to scrape them Question: I currently have a function that takes in a url string, read it to find x information and store it as a json file: def log_scrape(url): HEADERS = {‘User-Agent’: ‘Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/42.0.2311.135 Safari/537.36 Edge/12.246’} response = …

Python: quoted URL is not converted correctly on the website using requests Question: I’m trying to scrape some German sentences from Glosbe.com. The requested URL contains some utf-8 characters. The website doesn’t change the quoted characters to utf-8 characters after the request is done. The requested URl should look like this https://glosbe.com/de/hu/abkühlen But the requested …

InvalidSchema: No connection adapters were found for "link"? Question: I have a dataset with multiple links and I’m trying to get the text of all the links using the code below, but I’m getting a error message "InvalidSchema: No connection adapters were found for "’https://en.wikipedia.org/wiki/Wagner_Group’". Dataset: links ‘https://en.wikipedia.org/wiki/Wagner_Group’ ‘https://en.wikipedia.org/wiki/Vladimir_Putin’ ‘https://en.wikipedia.org/wiki/Islam_in_Russia’ The code I’m using to …

Not making list of urls in scrapy spider Question: I have created a scrapy spider that has to crawl the whole webpage and extract the urls. now I have to remove the social media URL for that I want to make a list of the URLs, but somehow it’s not working. when I try to …

Unable to load URL Question: import requests url = https://www.nseindia.com/get-quotes/equity?symbol=ACC data = requests.get(‘https://www.nseindia.com/get-quotes/equity?symbol=ACC”) print(data) I’m trying to load data from above url but failed. How to do that? I got a invalid syntax error. Asked By: Brijesh Chaurasia || Source Answers: You mean this? import requests data = requests.get(‘https://www.nseindia.com/get-quotes/equity?symbol=ACC’) print(data) Saying url = https://www.nseindia.com/get-quotes/equity?symbol=ACC is …