Remove leading and trailing slash / in python
Question:
I am using request.path to return the current URL in Django, and it is returning /get/category.
I need it as get/category (without leading and trailing slash).
How can I do this?
Answers:
>>> "/get/category".strip("/")
'get/category'
strip() is the proper way to do this.
def remove_lead_and_trail_slash(s):
if s.startswith('/'):
s = s[1:]
if s.endswith('/'):
s = s[:-1]
return s
Unlike str.strip(), this is guaranteed to remove at most one of the slashes on each side.
Another one with regular expressions:
>>> import re
>>> s = "/get/category"
>>> re.sub("^/|/$", "", s)
'get/category'
You can try:
"/get/category".strip("/")
I am using request.path to return the current URL in Django, and it is returning /get/category.
I need it as get/category (without leading and trailing slash).
How can I do this?
>>> "/get/category".strip("/")
'get/category'
strip() is the proper way to do this.
def remove_lead_and_trail_slash(s):
if s.startswith('/'):
s = s[1:]
if s.endswith('/'):
s = s[:-1]
return s
Unlike str.strip(), this is guaranteed to remove at most one of the slashes on each side.
Another one with regular expressions:
>>> import re
>>> s = "/get/category"
>>> re.sub("^/|/$", "", s)
'get/category'
You can try:
"/get/category".strip("/")