Skip first line(field) in loop using CSV file?

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When processing CSV data, how do I ignore the first line of data?

I am using python to open CSV file. I am using formula loop but I need to skip the first row because it has header.

So far I remember was something like this but it is missing something: I wonder if someone knows the code for what I am trying to do.

for row in kidfile:
    if row.firstline = false:  # <====== Something is missing here.
        continue
    if ......

Asked By: Raitis Kupce

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Answer 1

The best way of doing this is skipping the header after passing the file object to the csv module:

with open('myfile.csv', 'r', newline='') as in_file:
    reader = csv.reader(in_file)
    # skip header
    next(reader)
    for row in reader:
        # handle parsed row

This handles multiline CSV headers correctly.

Older answer:

Probably you want something like:

firstline = True
for row in kidfile:
    if firstline:    #skip first line
        firstline = False
        continue
    # parse the line

An other way to achive the same result is calling readline before the loop:

kidfile.readline()   # skip the first line
for row in kidfile:
    #parse the line

Answered By: Bakuriu

Answer 2

There are many ways to skip the first line. In addition to those said by Bakuriu, I would add:

with open(filename, 'r') as f:
    next(f)
    for line in f:

and:

with open(filename,'r') as f:
    lines = f.readlines()[1:]

Answered By: Andrea

Answer 3

csvreader.next()
Return the next row of the reader’s iterable object as a list, parsed according to the current dialect.

Answered By: user2037553

Skip first line(field) in loop using CSV file?

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