A good way to make long strings wrap to newline?

Question

In my project, I have a bunch of strings that are read in from a file. Most of them, when printed in the command console, exceed 80 characters in length and wrap around, looking ugly.

I want to be able to have Python read the string, then test if it is over 75 characters in length. If it is, then split the string up into multiple strings, then print one after the other on a new line.
I also want it to be smart, not cutting off full words. i.e. "The quick brown <newline> fox..." instead of "the quick bro<newline>wn fox...".

I’ve tried modifying similar code that truncates the string after a set length, but just trashes the string instead of putting it in a new line.

What are some methods I could use to accomplish this?

Asked By: Joshua Merriman

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Source

Answer 1

You could use textwrap module:

>>> import textwrap
>>> strs = "In my project, I have a bunch of strings that are read in from a file. Most of them, when printed in the command console, exceed 80 characters in length and wrap around, looking ugly."
>>> print(textwrap.fill(strs, 20))
In my project, I
have a bunch of
strings that are
read in from a file.
Most of them, when
printed in the
command console,
exceed 80 characters
in length and wrap
around, looking
ugly.

help on textwrap.fill:

>>> textwrap.fill?

Definition: textwrap.fill(text, width=70, **kwargs)
Docstring:
Fill a single paragraph of text, returning a new string.

Reformat the single paragraph in 'text' to fit in lines of no more
than 'width' columns, and return a new string containing the entire
wrapped paragraph.  As with wrap(), tabs are expanded and other
whitespace characters converted to space.  See TextWrapper class for
available keyword args to customize wrapping behaviour.

Use regex if you don’t want to merge a line into another line:

import re


strs = """In my project, I have a bunch of strings that are.
Read in from a file.
Most of them, when printed in the command console, exceed 80.
Characters in length and wrap around, looking ugly."""

print('n'.join(line.strip() for line in re.findall(r'.{1,40}(?:s+|$)', strs)))

# Reading a single line at once:
for x in strs.splitlines():
    print 'n'.join(line.strip() for line in re.findall(r'.{1,40}(?:s+|$)', x))

output:

In my project, I have a bunch of strings
that are.
Read in from a file.
Most of them, when printed in the
command console, exceed 80.
Characters in length and wrap around,
looking ugly.

Answered By: Ashwini Chaudhary

Answer 2

This is what the textwrap module is for. Try textwrap.fill(some_string, width=75).

Answered By: jwodder

Answer 3

This is similar to Ashwini’s answer but does not use re:

lim=75
for s in input_string.split("n"):
    if s == "": print
    w=0 
    l = []
    for d in s.split():
        if w + len(d) + 1 <= lim:
            l.append(d)
            w += len(d) + 1 
        else:
            print " ".join(l)
            l = [d] 
            w = len(d)
    if (len(l)): print " ".join(l)

Output when the input is your question:

In my project, I have a bunch of strings that are read in from a file.
Most of them, when printed in the command console, exceed 80 characters in
length and wrap around, looking ugly.

I want to be able to have Python read the string, then test if it is over
75 characters in length. If it is, then split the string up into multiple
strings, then print one after the other on a new line. I also want it to be
smart, not cutting off full words. i.e. "The quick brown <newline> fox..."
instead of "the quick bro<newline>wn fox...".

Answered By: perreal

Answer 4

string, max_width = input(), int(input())
result = wrap(string, max_width)
print(result)

def wrap(string, max_width):
    s=''
    for i in range(0,len(string),max_width):
        s=s+string[i:i+max_width]
        s=s+'n'
    return s

Answered By: pawan kumar

Answer 5

string, max_width = input(), int(input())
result = wrap(string, max_width)
print(result)

def wrap(string, max_width):
    s=''
    for i in range(0,len(string),max_width):
        s+=string[i:i+max_width]
        s+='n'
    return s

Answered By: user12314353

Answer 6

In python-3

import textwrap
def wrap(string, max_width):
    return 'n'.join(textwrap.wrap(string,max_width))

Input:

wrap(ABCDEFGHIJKLIMNOQRSTUVWXYZ, 4)

output:

ABCD
EFGH
IJKL
IMNO
QRST
UVWX
YZ

Answered By: Biman Pal

Answer 7

import textwrap

def wrap(string, max_width):
    return textwrap.fill(string,max_width)

if __name__ == '__main__':
    string, max_width = input(), int(input())
    result = wrap(string, max_width)
    print(result)

input:
ABCDEFGHIJKLIMNOQRSTUVWXYZ "n"
4

output:
ABCD"n"
EFGH"n"
IJKL"n"
IMNO"n"
QRST"n"
UVWX"n"
YZ"n"

Answered By: Harshit Bhatt

Answer 8

Without using any inbuilt function, this will wrap the string into a paragraph of input width. Given you have a long string get the length of the string, use range(0,len(string),max_width) so that it will iterate till it becomes empty. Empty string is assigning new line. One thing to note here is when you return(string[i:i:i+max_width])

def wrap(string, max_width):
    empty_string=''
    for i in range(0,len(string),max_width):
        empty_string+=string[i:i+max_width]
        print(string[i:i+max_width])
        empty_string+='n'
    return (string[i:i:i+max_width])
    if __name__ == '__main__':
    string, max_width = input(), int(input())
    result = wrap(string, max_width)
    print(result)

Answered By: Rashmi mohapatra

A good way to make long strings wrap to newline?

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