Multiple try codes in one block

Extract (refactor) your statements. And use the magic of and and or to decide when to short-circuit.

def a():
    try: # a code
    except: pass # or raise
    else: return True

def b():
    try: # b code
    except: pass # or raise
    else: return True

def c():
    try: # c code
    except: pass # or raise
    else: return True

def d():
    try: # d code
    except: pass # or raise
    else: return True

def main():   
    try:
        a() and b() or c() or d()
    except:
        pass

If you don’t want to chain (a huge number of) try-except clauses, you may try your codes in a loop and break upon 1st success.

Example with codes which can be put into functions:

for code in (
    lambda: a / b,
    lambda: a / (b + 1),
    lambda: a / (b + 2),
    ):
    try: print(code())
    except Exception as ev: continue
    break
else:
    print("it failed: %s" % ev)

Example with arbitrary codes (statements) directly in the current scope:

for i in 2, 1, 0:
    try:
        if   i == 2: print(a / b)
        elif i == 1: print(a / (b + 1))
        elif i == 0: print(a / (b + 2))
        break        
    except Exception as ev:
        if i:
            continue
        print("it failed: %s" % ev)

You can use fuckit module.
Wrap your code in a function with @fuckit decorator:

@fuckit
def func():
    code a
    code b #if b fails, it should ignore, and go to c.
    code c #if c fails, go to d
    code d

Lets say each code is a function and its already written then the following can be used to iter through your coding list and exit the for-loop when a function is executed without error using the "break".

def a(): code a
def b(): code b
def c(): code c
def d(): code d

for func in [a, b, c, d]:  # change list order to change execution order.
   try:
       func()
       break
   except Exception as err:
       print (err)
       continue

I used "Exception " here so you can see any error printed. Turn-off the print if you know what to expect and you’re not caring (e.g. in case the code returns two or three list items (i,j = msg.split(‘.’)).

You could try a for loop

for func,args,kwargs in zip([a,b,c,d], 
                            [args_a,args_b,args_c,args_d],
                            [kw_a,kw_b,kw_c,kw_d]):
    try:
       func(*args, **kwargs)
       break
    except:
       pass

This way you can loop as many functions as you want without making the code look ugly

I use a different way, with a new variable:

continue_execution = True
try:
    command1
    continue_execution = False
except:
    pass
if continue_execution:
    try:
        command2
    except:
        command3

to add more commands you just have to add more expressions like this:

try:
    commandn
    continue_execution = False
except:
    pass

I ran into this problem, but then it was doing the things in a loop which turned it into a simple case of issueing the continue command if successful. I think one could reuse that technique if not in a loop, at least in some cases:

while True:
    try:
        code_a
        break
    except:
        pass

    try:
        code_b
        break
    except:
        pass

    etc

    raise NothingSuccessfulError

Like Elazar suggested:
"I think a decorator would fit here."

# decorator
def test(func):
    def inner(*args, **kwargs):
        try:
            func(*args, **kwargs)
        except: pass
    return inner

# code blocks as functions
@test
def code_a(x):
    print(1/x)

@test
def code_b(x):
    print(1/x)

@test
def code_c(x):
    print(1/x)

@test
def code_d(x):
    print(1/x)

# call functions
code_a(0)
code_b(1)
code_c(0)
code_c(4)

output:

1.0
0.25