How to check if a tuple contains an element in Python?
Question:
I tried to find the available methods but couldn’t find it. There is no contains
. Should I use index
? I just want to know if the item exists, don’t need the index of it.
Answers:
You use in
.
if element in thetuple:
#whatever you want to do.
Be careful with that:
return Oops.
use Set: d= {…}
def simha():
d = ('this_is_valid')
b = 'valid'
if b in d:
print("Oops!!!!!")
simha()
if "word" in str(tuple):
# You can convert the tuple to str too
i has the same problem and only worked to me after the convert str()
Use as follows: variable_name in tuple
animals = ('Dog', 'Elephant', 'Fox')
animal_name = 'Fox'
Check if an x is in animals
tuple:
if animal_name in animals :
# Fox is existing in animals
Check if an x is NOT in animals
tuple:
if not animal_name in animals :
# Fox is not existing in animals
I tried to find the available methods but couldn’t find it. There is no contains
. Should I use index
? I just want to know if the item exists, don’t need the index of it.
You use in
.
if element in thetuple:
#whatever you want to do.
Be careful with that:
return Oops.
use Set: d= {…}
def simha():
d = ('this_is_valid')
b = 'valid'
if b in d:
print("Oops!!!!!")
simha()
if "word" in str(tuple):
# You can convert the tuple to str too
i has the same problem and only worked to me after the convert str()
Use as follows: variable_name in tuple
animals = ('Dog', 'Elephant', 'Fox')
animal_name = 'Fox'
Check if an x is in animals
tuple:
if animal_name in animals :
# Fox is existing in animals
Check if an x is NOT in animals
tuple:
if not animal_name in animals :
# Fox is not existing in animals