How do I log an exception at warning- or info-level with traceback using the python logging framework?

Question

Using something like this:

try:
   # Something...
except Exception as excep:
   logger = logging.getLogger("component")
   logger.warning("something raised an exception: " + excep)
   logger.info("something raised an exception: " + excep)

I would rather not have it on the error-level cause in my special case it is not an error.

Asked By: Morten Holdflod Møller

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Source

Answer 1

From the logging documentation:

There are three keyword arguments in kwargs which are inspected: exc_info, stack_info, and extra.

If exc_info does not evaluate as false, it causes exception information to be added to the logging message. If an exception tuple (in the format returned by sys.exc_info()) or an exception instance is provided, it is used; otherwise, sys.exc_info() is called to get the exception information.

So do:

logger.warning("something raised an exception:", exc_info=True)

Answered By: Douglas Leeder

Answer 2

Here is one that works (python 2.6.5).

logger.critical("caught exception, traceback =", exc_info=True)

Answered By: Scubahubby

Answer 3

You can try this:

from logging import getLogger

logger = getLogger('warning')

try:
    # Somethings that is wrong.

except Exception as exp:
    logger.warning("something raised an exception: " , exc_info=True)
    logger.warning("something raised an exception: {}".format(exp))  # another way

Answered By: Benyamin Jafari

How do I log an exception at warning- or info-level with traceback using the python logging framework?

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